Take K of Each Character From Left and Right [LC#2516]

You are given a string s consisting of the characters ‘a’, ‘b’, and ‘c’ and a non-negative integer k. Each minute, you may take either the leftmost character of s, or the rightmost character of s. Return the minimum number of minutes needed for you to take at least k of each character, or return -1 if it is not possible to take k of each character.

Intuition

We are looking for a largest window that can be removed without making count of all characters going below k

Code

def take_characters(s: str, k: int) -> int:
    if k == 0 : return 0 
    count = Counter({"a": 0, "b": 0, "c": 0})
    for char in s:
        count[char] += 1

    if min(count.values()) < k:
        return -1

    max_window = 0
    left = 0
    for right in range(len(s)):
        count[s[right]] -= 1
        while left <= right and min(count.values()) < k:
            count[s[left]] += 1
            left += 1
        max_window = max(max_window, right - left + 1)
    return len(s) - max_window

Time complexity